Aufgabe 2 – Mit gemischten Zahlen rechnen
Berechne die Lösung.
a) \(2\,\frac{1}{6}+4\,\frac{3}{7}+1\,\frac{1}{2}\)
b) \(4\,\frac{3}{7}-2\,\frac{1}{7}\)
c) \(1\,\frac{6}{7}+\frac{4}{7}-2\frac{1}{3}\)
d) \(3\,\frac{3}{20}+\frac{4}{5}-2\,\frac{3}{4}\)
Lösung
a) \begin{align}2\,\frac{1}{6}+4\,\frac{3}{7}+1\,\frac{1}{2}&=2+4+1+\left(\frac{1}{6}+\frac{3}{7}+\frac{1}{2}\right) \\[0.2cm]&=7+\left(\frac{7}{42}+\frac{18}{42}+\frac{21}{42}\right)=7+\frac{46}{42} \\[0.2cm]&=7+1+\frac{4}{42}=8\,\frac{2}{21}\end{align}
b) \begin{align}4\,\frac{3}{7}-2\,\frac{1}{7}&=4-2+\left(\frac{3}{7}-\frac{1}{7}\right) \\[0.2cm] &=2+\frac{2}{7}=2\,\frac{2}{7}\end{align}
c) \begin{align}1\,\frac{6}{7}+\frac{4}{7}-2\frac{1}{3}&=1+\left(\frac{6}{7}+\frac{4}{7}\right)-2\,\frac{1}{3} \\[0.2cm]&=1+\frac{10}{7}-2\,\frac{1}{3}=1+1+\frac{3}{7}-2\frac{1}{3} \\[0.2cm]&=1+1-2\left(\frac{3}{7}-\frac{1}{3}\right)=\frac{9}{21}-\frac{7}{21}=\frac{2}{21}\end{align}
d) \begin{align}3\,\frac{3}{20}+\frac{4}{5}-2\,\frac{3}{4}&=3+\left(\frac{3}{20}+\frac{4}{5}\right)-2\,\frac{3}{4} \\[0.2cm] &=3+\left(\frac{3}{20}+\frac{16}{20}\right)-2\,\frac{3}{4}=3+\frac{19}{20}-2\,\frac{3}{4} \\[0.2cm] &=3-2+\left(\frac{19}{20}-\frac{3}{4}\right)=1+\left(\frac{19}{20}-\frac{15}{20}\right) \\[0.2cm] &=1+\frac{4}{20}=1+\frac{1}{5}=1\,\frac{1}{5}\end{align}